Russia Gold 10 Rouble (1898-1911) melt value — $1,092.82 at $4,390.60 gold

Melt / coin$1,092.82

Gold spot$4,390.60

AGW0.24890 oz

Gross weight8.603 g

Fineness89.99%

Gross troy oz0.2766

Coins / oz4.02

How this melt is figured

A Russia Gold 10 Rouble (1898-1911) weighs 8.603 grams at 89.99% fine. That is 0.24890 troy ounces of pure gold (AGW). Melt = 0.24890 × today’s gold spot of $4,390.60.

Date and mintmark do not change the metal. An early date and a common date of this type have the same melt. Collector value — what someone will pay above the metal — is a different question. For sold prices see Sold Comps.

Quick amounts

Using $4,390.60 gold.

You have	Pure oz	Melt
1 coin	0.2489	$1,092.82
10 coins	2.4890	$10,928.20
20 coins	4.9780	$21,856.41

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Questions people ask

How much pure gold is in a Russia Gold 10 Rouble (1898-1911)?

Mint spec is 8.603 grams at 89.99% fine, which is 0.24890 troy oz of pure gold (AGW). Date and mintmark do not change that.

What is a Russia Gold 10 Rouble (1898-1911) worth in melt today?

At gold spot of $4,390.60 per troy oz, one coin’s melt is $1,092.82. Multiply by how many you have. A rare date or a nice grade can sell for more than melt.

How many Russia Gold 10 Rouble (1898-1911)s equal one ounce of gold?

About 4.02 coins equal 1.00 troy oz of pure gold at mint weight.

Does mintmark change the melt value?

No. A Philadelphia, Denver, or San Francisco coin of this type has the same metal. Melt is type × composition, not date or mintmark.

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How this melt is figured

Quick amounts

Where gold has been.

Email me if this coin’s melt crosses a number I set.

Same metal, nearby coins.

Questions people ask