Spot as of Sep 6, 2026 9:20 PM · $1 move in gold changes this coin by $0.01
How this melt is figured
A California Fractional Gold 50¢ (octagonal, typical) weighs 0.500 grams at 88.33% fine. That is 0.01420 troy ounces of pure gold (AGW). Melt = 0.01420 × today’s gold spot of $4,390.60.
Date and mintmark do not change the metal. An early date and a common date of this type have the same melt. Collector value — what someone will pay above the metal — is a different question. For sold prices see Sold Comps.
Quick amounts
Using $4,390.60 gold.
| You have | Pure oz | Melt |
|---|---|---|
| 1 coin | 0.0142 | $62.35 |
| 10 coins | 0.1420 | $623.47 |
| 20 coins | 0.2840 | $1,246.93 |
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Questions people ask
How much pure gold is in a California Fractional Gold 50¢ (octagonal, typical)?
Mint spec is 0.500 grams at 88.33% fine, which is 0.01420 troy oz of pure gold (AGW). Date and mintmark do not change that.
What is a California Fractional Gold 50¢ (octagonal, typical) worth in melt today?
At gold spot of $4,390.60 per troy oz, one coin’s melt is $62.35. Multiply by how many you have. A rare date or a nice grade can sell for more than melt.
How many California Fractional Gold 50¢ (octagonal, typical)s equal one ounce of gold?
About 70.42 coins equal 1.00 troy oz of pure gold at mint weight.
Does mintmark change the melt value?
No. A Philadelphia, Denver, or San Francisco coin of this type has the same metal. Melt is type × composition, not date or mintmark.
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