Spot as of Sep 6, 2026 9:20 PM · $1 move in gold changes this coin by $0.09
How this melt is figured
A Morocco Gold 10 Franc (1921-1925) weighs 3.230 grams at 89.84% fine. That is 0.09330 troy ounces of pure gold (AGW). Melt = 0.09330 × today’s gold spot of $4,390.60.
Date and mintmark do not change the metal. An early date and a common date of this type have the same melt. Collector value — what someone will pay above the metal — is a different question. For sold prices see Sold Comps.
Quick amounts
Using $4,390.60 gold.
| You have | Pure oz | Melt |
|---|---|---|
| 1 coin | 0.0933 | $409.64 |
| 10 coins | 0.9330 | $4,096.43 |
| 20 coins | 1.8660 | $8,192.86 |
Gold chart
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Questions people ask
How much pure gold is in a Morocco Gold 10 Franc (1921-1925)?
Mint spec is 3.230 grams at 89.84% fine, which is 0.09330 troy oz of pure gold (AGW). Date and mintmark do not change that.
What is a Morocco Gold 10 Franc (1921-1925) worth in melt today?
At gold spot of $4,390.60 per troy oz, one coin’s melt is $409.64. Multiply by how many you have. A rare date or a nice grade can sell for more than melt.
How many Morocco Gold 10 Franc (1921-1925)s equal one ounce of gold?
About 10.72 coins equal 1.00 troy oz of pure gold at mint weight.
Does mintmark change the melt value?
No. A Philadelphia, Denver, or San Francisco coin of this type has the same metal. Melt is type × composition, not date or mintmark.
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